document.write( "Question 1022328: A jeweler maker has 20 ounces of a gold alloy worth $160 an ounce and 10 ounce of a silver alloy worth $140 an ounce. How many ounces of another alloy at $124 an ounce must she add to these in order to have a mixture of the three that she can use to make 3-ounce jewelry worth $438 a piece? \n" ); document.write( "
Algebra.Com's Answer #638029 by ankor@dixie-net.com(22740)\"\" \"About 
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A jeweler maker has 20 ounces of a gold alloy worth $160 an ounce and 10 ounce of a silver alloy worth $140 an ounce.
\n" ); document.write( " How many ounces of another alloy at $124 an ounce must she add to these in order to have a mixture of the three that she can use to make 3-ounce jewelry worth $438 a piece?
\n" ); document.write( ":
\n" ); document.write( "He doesn't need any of the $124 an ounce to to make this jewelry
\n" ); document.write( ":
\n" ); document.write( "let x = amt of gold alloy required to make the 3 oz jewelry
\n" ); document.write( "then
\n" ); document.write( "(3-x) = amt of silver alloy required
\n" ); document.write( ":
\n" ); document.write( "160x + 140(3-x) = 438
\n" ); document.write( "160x + 420 - 140x = 438
\n" ); document.write( "160x - 140x = 438 - 420
\n" ); document.write( "20x = 18
\n" ); document.write( "x = 18/20
\n" ); document.write( "x = .9 oz of the $160 per oz alloy
\n" ); document.write( "then
\n" ); document.write( "3 - .9 = 2.1 oz of the $140 per oz alloy
\n" ); document.write( ":
\n" ); document.write( ":
\n" ); document.write( "Check this
\n" ); document.write( ".9(160) + 2.1(140) =
\n" ); document.write( "144 + 294 = 438
\n" ); document.write( ":
\n" ); document.write( ":
\n" ); document.write( "Note the jewelry 438/3 = $146 per oz, which is between the $160 and $140 per oz
\n" ); document.write( "So no need for $124 per oz stuff \n" ); document.write( "
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