document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1022286>Question 1022286</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A rectangle has length of 28 cm & breadth of 12cm.what is the area of the least number of these rectangles used to form the smallest square possible?<BR>\n" );
document.write( "I cant get this one please help me... </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #638007 by </B><A HREF=/tutors/aboutme.mpl?userid=engsaoudah><B>engsaoudah(9)</B></A><img src=\"/images/stars/stars-05.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=engsaoudah><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=638007\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\">   find the factors of the side lengths so that we can work out a square shape to make if we simply placed them side by side. By finding the factors we can find the lowest common multiple of the two numbers.\r<BR>\n" );
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document.write( "12 = 2 x 2 x 3<BR>\n" );
document.write( "28 = 2 x 2 x 7\r<BR>\n" );
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document.write( "2 x 2 x 3 x 7 = 84\r<BR>\n" );
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document.write( "So if we placed them side by side we would get an 84cm by 84cm square. This would involve 21 rectangles, with 3 rows of 7, as 84/12 = 7 and 84/28 = 3. So the area will be 84 x 84 which equals 7056cm^2 </SPAN>\n" );
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