document.write( "Question 1022258: The width of a room is three-fifths of its length. When the width is increased by 2 metres and the length is decreased by 2 metres the resultant shape is a square.
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Algebra.Com's Answer #637994 by josgarithmetic(39625)\"\" \"About 
You can put this solution on YOUR website!
\"w=%283%2F5%29L\"\r
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\n" ); document.write( "\n" ); document.write( "Changes to dimensions:
\n" ); document.write( "Width to w+2, length to L-2;
\n" ); document.write( "\"w%2B2=L-2\"\r
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\n" ); document.write( "\n" ); document.write( "Solve the system \"system%28w=%283%2F5%29L%2Cw%2B2=L-2%29\".\r
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\n" ); document.write( "\n" ); document.write( "\"w-L=-4\"
\n" ); document.write( "\"L-w=4\"
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\n" ); document.write( "\"5w=3L\"
\n" ); document.write( "\"3L-5w=0\"
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\n" ); document.write( "New system to have the same solution can be \"system%28L-w=4%2C3L-5w=0%29\".\r
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\n" ); document.write( "\n" ); document.write( "From that , \"system%283L-3w=12%2C3L-5w=0%29\"
\n" ); document.write( "\"3L-3w-3L-%28-5w%29=12-0\"
\n" ); document.write( "\"2w=12\"
\n" ); document.write( "\"highlight%28w=6%29\" and \"L=%285%2F3%29w=%285%2F3%29%2A6=highlight%2810=L%29\".\r
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\n" ); document.write( "\n" ); document.write( "Full use of the substitution method would have also been good. I arranged the two system equation to start with elimination method.
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