document.write( "Question 87923This question is from textbook Introductory and Intermediate Algebra
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document.write( ": Could you please help with the following problem: A picture 9 inches wide and 12 inches long is surrounded by a frame of uniform width. The area of the frame only is 162 square inches. Find the width of the frame.\r
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document.write( "Thank you very much for any help you can provide. \n" );
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Algebra.Com's Answer #63796 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! A picture 9 inches wide and 12 inches long is surrounded by a frame of uniform width. The area of the frame only is 162 square inches. Find the width of the frame. \n" ); document.write( "------------- \n" ); document.write( "Draw the picture of the frame around the picture. \n" ); document.write( "---------------------------- \n" ); document.write( "Let the width of the frame be \"x\"inches. \n" ); document.write( "----------------------------- \n" ); document.write( "Area of picture with frame around is length*width \n" ); document.write( "Width = 9 + 2x inches \n" ); document.write( "length = 12 + 2x inches \n" ); document.write( "--------- \n" ); document.write( "Larger area = (9+2x)(12+2x) \n" ); document.write( "=2(9+2x)(6+x) \n" ); document.write( "=2[54+21x+2x^2] \n" ); document.write( "=4x^2 + 42x + 108 \n" ); document.write( "--------------- \n" ); document.write( "Area of frame = larger area - 9*12 \n" ); document.write( "= 4x^2 + 42x +108 - 108 \n" ); document.write( "= 4x^2 + 42x \n" ); document.write( "------------------- \n" ); document.write( "Area of frame = 162 sq. in. \n" ); document.write( "4x^2+42x= 162 \n" ); document.write( "2x^2 + 21x -81 = 0 \n" ); document.write( "x = [-21+33]/4 = 3 or x = [-21-33]/4 = -54/4 = -27/2 \n" ); document.write( "---------------------- \n" ); document.write( "Realistic Answer: width = 3 inches \n" ); document.write( "============================ \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( " |