document.write( "Question 1022209: 2x-3y+3z=-3
\n" ); document.write( " 6y+z=8
\n" ); document.write( "2x+3y+4z=9\r
\n" ); document.write( "\n" ); document.write( "Solve the system of equations \n" ); document.write( "

Algebra.Com's Answer #637953 by Edwin McCravy(20054) $\"\"$ $\"About$

You can put this solution on YOUR website!

\r\n" );
document.write( "\r\n" );
document.write( "\r\n" );
document.write( "Since x is already eliminated from the\r\n" );
document.write( "2nd equation, we will eliminate x\r\n" );
document.write( "from the 1st and 3rd by multiplying the\r\n" );
document.write( "1st equation through by -1 and adding\r\n" );
document.write( "it term by term to the 3rd equation like this:\r\n" );
document.write( "\r\n" );
document.write( "-2x+3y-3z=3\r\n" );
document.write( " 2x+3y+4z=9\r\n" );
document.write( "------------\r\n" );
document.write( "    6y+ z=12\r\n" );
document.write( "\r\n" );
document.write( "Now we take that with the 2nd original equation\r\n" );
document.write( "and we have a system of 2 equations in 2 unknowns:\r\n" );
document.write( "\r\n" );
document.write( "\r\n" );
document.write( "\r\n" );
document.write( "However we can see that if 6y+z=8, then 6y+z cannot\r\n" );
document.write( "equal 12, so there is no solution.\r\n" );
document.write( "\r\n" );
document.write( "This is an inconsistent system of equations.\r\n" );
document.write( "\r\n" );
document.write( "Edwin

\r
\n" ); document.write( "\n" ); document.write( " \n" ); document.write( "

\n" );