document.write( "Question 87917: X^3 – 5x^2 + 2x + 20 divided by (x-3) gives a remainder of?? \n" ); document.write( "
Algebra.Com's Answer #63795 by rapaljer(4671)\"\" \"About 
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You can do this the obvious way, by dividing the x-3 into the polynomial. There are two ways to do this: long division and synthetic division.\r
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\n" ); document.write( "\n" ); document.write( "However, you can also do this by substitution.
\n" ); document.write( "If P(x) = X^3 – 5x^2 + 2x + 20, then the remainder after division by x-3 is P(3).\r
\n" ); document.write( "\n" ); document.write( "P(3) = 3^3 -5*3^2 + 2*3 + 20
\n" ); document.write( "P(3) = 27 - 45 + 6 + 20
\n" ); document.write( "P(3)= 8\r
\n" ); document.write( "\n" ); document.write( "The remainder is 8. \r
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\n" ); document.write( "\n" ); document.write( "You can also check this with a graphing calculator. You can graph the function y1=X^3 – 5x^2 + 2x + 20, and evaluate the function at x = 3. With a TI 83, 84, or 86, after you graph the function, you can look in the TABLE and look for x= 3. Or you can just hit the TRACE button, and type the number 3. The calculator gives the x and y value. The y value is the answer to the problem. \r
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\n" ); document.write( "\n" ); document.write( "R^2 Retired from SCC
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