document.write( "Question 1022144: The width of a rectangular TV screen is 14.5 cm more than the height. If the diagonal is 68.6 cm, find the dimensions of the screen. \n" ); document.write( "
Algebra.Com's Answer #637899 by ikleyn(52814)\"\" \"About 
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\n" ); document.write( "The width of a rectangular TV screen is 14.5 cm more than the height.
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document.write( "Let x be the height measure in centimeters.\r\n" );
document.write( "Then the width measure is (x + 14.5), in accordance with the condition.\r\n" );
document.write( "The diagonal is (Pythagorean theorem)\r\n" );
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document.write( "\"sqrt%28x%5E2+%2B+%28x%2B14.5%29%5E2%29\".\r\n" );
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document.write( "According with the condition, the diagonal measure is 68.6 cm.\r\n" );
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document.write( "It gives you an equation\r\n" );
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document.write( "\"x%5E2+%2B+%28x%2B14.5%29%5E2\" = \"68.6%5E2\".\r\n" );
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document.write( "Simplify it:\r\n" );
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document.write( "\"x%5E2+%2B+x%5E2+%2B+29x+%2B+14.5%5E2+-+68.6%5E2\" = \"0\",\r\n" );
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document.write( "\"2x%5E2+%2B+29x+-+4495.71\" = \"0\".\r\n" );
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document.write( "Apply the quadratic formula. You will get\r\n" );
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document.write( "\"x%5B1%2C2%5D\" = \"%28-29+%2B-+sqrt%2829%5E2+%2B+4%2A2%2A4495.71%29%29%2F4\" = \"%28-29+%2B-+sqrt%2836806.68%29%29%2F4\" = \"%28-29+%2B-+191.85%29%2F4\".\r\n" );
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document.write( "The positive root (which only suits the condition) is 40.71.\r\n" );
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document.write( "The height of the screen is 40.71 cm.\r\n" );
document.write( "The width is  40.71 + 14.5 = 55.21 cm.\r\n" );
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