document.write( "Question 1022152: Jeffrey's father is four times as old as he is the sum of their ages is 50 years how old is each \n" ); document.write( "
Algebra.Com's Answer #637883 by addingup(3677)![]() ![]() You can put this solution on YOUR website! F = 4J (four times Jeffrey = father's age) \n" ); document.write( "F+J = 50 substitute for F: \n" ); document.write( "4J+J = 50 \n" ); document.write( "5j = 50 divide both sides by 5 to get your answer \n" ); document.write( " |