document.write( "Question 87868: Solve the quadratic equation by completing the square\r
\n" ); document.write( "\n" ); document.write( "x^2-6x-3=0\r
\n" ); document.write( "\n" ); document.write( "Thanks in advance.
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Algebra.Com's Answer #63787 by rapaljer(4671)\"\" \"About 
You can put this solution on YOUR website!
First add +3 to each side of the equation:\r
\n" ); document.write( "\n" ); document.write( "x^2-6x-3=0
\n" ); document.write( "x^2 -6x + ___ = 3+ ____ \r
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\n" ); document.write( "\n" ); document.write( "Take half of the x coefficient, -6, which is -3, and square which is 9. Add +9 to each side:
\n" ); document.write( "\"x%5E2+-6x%2B+9=+3%2B9\"
\n" ); document.write( "\"%28x-3%29%5E2+=+12\"\r
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\n" ); document.write( "\n" ); document.write( "Square root both sides:
\n" ); document.write( "\"x-3=+0%2B-sqrt%2812%29\"\r
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\n" ); document.write( "\n" ); document.write( "Add +3 to each side:
\n" ); document.write( "\"x=+3%2B-sqrt%2812%29+\"\r
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\n" ); document.write( "\n" ); document.write( "Simplify the square root:
\n" ); document.write( "\"x=+3%2B-sqrt%284%29%2Asqrt%283%29+\"
\n" ); document.write( "\"x=+3%2B2%2Asqrt%283%29+\" or \"x=3-2%2Asqrt%283%29+\"\r
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\n" ); document.write( "\n" ); document.write( "R^2 Retired from SCC
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