document.write( "Question 1022124: Please help , add 2C1 + 2C2 + 3C2 expressing your answer as a single binomial coefficient.Thanks in advance. \n" ); document.write( "
Algebra.Com's Answer #637856 by Edwin McCravy(20055)![]() ![]() You can put this solution on YOUR website! \r\n" ); document.write( "Learn how Pascal's triangle of binomial coefficients\r\n" ); document.write( "works:\r\n" ); document.write( "\r\n" ); document.write( "If we add any two numbers which are side by side, we \r\n" ); document.write( "will always get the number which is between and below \r\n" ); document.write( "them:\r\n" ); document.write( "\r\n" ); document.write( "\r\n" ); document.write( "\r\n" ); document.write( " 0C0=1\r\n" ); document.write( "\r\n" ); document.write( " 1C0=1 1C1=1 \r\n" ); document.write( "\r\n" ); document.write( " 2C0=1 2C1=2 2C2=1\r\n" ); document.write( "\r\n" ); document.write( " 3C0=1 3C1=3 3C2=3 3C3=1\r\n" ); document.write( "\r\n" ); document.write( " 4C0=1 4C1=4 4C2=6 4C3=4 4C4=1 \r\n" ); document.write( "\r\n" ); document.write( "\r\n" ); document.write( "2C1 + 2C2 + 3C2\r\n" ); document.write( "\r\n" ); document.write( "Add just the first two:\r\n" ); document.write( "\r\n" ); document.write( "If we add 2C1=2 and 2C2=1, they are side by side, so we\r\n" ); document.write( "get the number between and below them which is 3C2=3.\r\n" ); document.write( "Then if we add 3C2 to that we get 2(3C2)=6.\r\n" ); document.write( "\r\n" ); document.write( "Then we notice that 4C2 also = 6, and 4C2 is a single\r\n" ); document.write( "binomial coefficient, so the answer is 4C2.\r\n" ); document.write( "\r\n" ); document.write( "Edwin\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |