document.write( "Question 1020742: Paul invested three times as much in an account paying 4% interest as he did in an account paying 1% interest. If the total interest paid was $390, how much did he invest in each account? \n" ); document.write( "
Algebra.Com's Answer #637830 by fractalier(6550)\"\" \"About 
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Call what he invests at 1%, x. Then he invests 3x at 4%. We write this as
\n" ); document.write( ".01x + (.04)(3x) = 390
\n" ); document.write( ".01x + .12x = 390
\n" ); document.write( ".13x = 390
\n" ); document.write( "x = $3000 at 1% and then
\n" ); document.write( "3x = $9000 at 4%
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