document.write( "Question 87875: Geometry. The lenght of a rectangle is 2 in. more than twice its width. If the perimeter of the rectangel is 34 in., find the dimensions of the rectangle. \n" ); document.write( "
Algebra.Com's Answer #63781 by rapaljer(4671)\"\" \"About 
You can put this solution on YOUR website!
Let x = width\r
\n" ); document.write( "\n" ); document.write( "2x+2 = length\r
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\n" ); document.write( "\n" ); document.write( "The perimeter is 34 inches.\r
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\n" ); document.write( "\n" ); document.write( "2W + 2L = 34
\n" ); document.write( "2(___)+2(____)=34
\n" ); document.write( "2(x) + 2(2x+2) = 34
\n" ); document.write( "2x + 4x + 4 = 34
\n" ); document.write( "6x + 4 = 34
\n" ); document.write( "6x+4-4 = 34 - 4
\n" ); document.write( "6x = 30
\n" ); document.write( "x=5 Width\r
\n" ); document.write( "\n" ); document.write( "2x+2 = Length
\n" ); document.write( "2(5)+2 = 12 Length\r
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\n" ); document.write( "\n" ); document.write( "Check:
\n" ); document.write( "2W + 2L = P
\n" ); document.write( "2(5)+2(12) = 34
\n" ); document.write( "10 +24 = 34\r
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\n" ); document.write( "\n" ); document.write( "By the way, I have a TON of these problems in a Lesson Plan in algebra.com. See also my own website by clicking on my tutor name \"rapaljer\" anywhere in algebra.com. Then go to the \"MATH IN LIVING COLOR\" page, and look for \"Basic Algebra\", then \"Section 1.10 Word Problems\"!!\r
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\n" ); document.write( "\n" ); document.write( "R^2 Retired from SCC\r
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