document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1022096>Question 1022096</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Jen Butler has been pricing&#8203; Speed-Pass train fares for a group trip to New York.  Three adults and four children must pay $ 136.<BR>\n" );
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document.write( "Two adults and three children must pay $ 97.<BR>\n" );
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document.write( "Find the price of the&#8203; adult's ticket and the price of a&#8203; child's ticket. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #637806 by </B><A HREF=/tutors/aboutme.mpl?userid=rothauserc><B>rothauserc(4718)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=rothauserc><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=rothauserc><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=637806\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> we have two equations in two unknowns<BR>\n" );
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document.write( "1) 3a + 4c = 136<BR>\n" );
document.write( "2) 2a + 3c = 97<BR>\n" );
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document.write( "solve equation 1 for c<BR>\n" );
document.write( "4c = 136 -3a<BR>\n" );
document.write( "c = 34 -3a/4<BR>\n" );
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document.write( "substitute for c in equation 2<BR>\n" );
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document.write( "2a +3(34 -3a/4) = 97<BR>\n" );
document.write( "2a +102 -9a/4 = 97<BR>\n" );
document.write( "-a/4 = -5<BR>\n" );
document.write( "a = 20<BR>\n" );
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document.write( "60 + 4c = 136<BR>\n" );
document.write( "4c = 76<BR>\n" );
document.write( "c = 19<BR>\n" );
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document.write( "adult's ticket costs $20<BR>\n" );
document.write( "child's ticket costs $19<BR>\n" );
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