document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1022095>Question 1022095</A>: <I><SPAN STYLE=\"word-break: break-all;\"> An employment agency specializing in temporary construction help pays heavy equipment operators $ 120<BR>\n" );
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document.write( "per day and general laborers $ 98<BR>\n" );
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document.write( "per day.  If thirty<BR>\n" );
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document.write( "people were hired and the payroll was $ 3556<BR>\n" );
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document.write( "how many heavy equipment operators were&#8203; employed?  How many&#8203; laborers? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #637802 by </B><A HREF=/tutors/aboutme.mpl?userid=fractalier><B>fractalier(6550)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=fractalier><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=fractalier><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=637802\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Call the numbers of heavy equipment operators and general laborers hired, x and y.  Then we write<BR>\n" );
document.write( "x + y = 30  and<BR>\n" );
document.write( "120x + 98y = 3556<BR>\n" );
document.write( "Now multiply the top equation by 120 and subtract and we get<BR>\n" );
document.write( "120x + 98y = 3556<BR>\n" );
document.write( "-(120x + 120y = 3600)<BR>\n" );
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document.write( "-22y = - 44<BR>\n" );
document.write( "y = 2 general laborers<BR>\n" );
document.write( "That means there were<BR>\n" );
document.write( "x = 28 heavies </SPAN>\n" );
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