document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1022073>Question 1022073</A>: <I><SPAN STYLE=\"word-break: break-all;\"> I need help with this please: Find the area of the region in the first quadrant bounded by the graph of y = x <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=sqrt%284+-+x%5E2%29 ALIGN=MIDDLE  ALT=\"sqrt%284+-+x%5E2%29\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #637795 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=637795\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> This is the integral between 0 and 2 of x*sqrt(4-x^2)<BR>\n" );
document.write( "let u=4-x^2<BR>\n" );
document.write( "du=-2xdx<BR>\n" );
document.write( "(-1/2) du=xdx<BR>\n" );
document.write( "integral of -(1/2)u^(1/2)<BR>\n" );
document.write( "(-1/2)(2/3)u^(3/2)<BR>\n" );
document.write( "(-1/3)*(4-x^2)^(3/2) evaluated at 0 and 2.<BR>\n" );
document.write( "at 2, (-1/3)(4-x^2)^(3/2)=0.<BR>\n" );
document.write( "at 0, -(-1/3)(4-x^2)^(3/2)=8, because 4^(3/2)=-(-8/3)=8/3<BR>\n" );
document.write( "Area is 8/3<BR>\n" );
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