document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1021996>Question 1021996</A>: <I><SPAN STYLE=\"word-break: break-all;\"> three times the first number decreased by a second number is 4. the first number is increased by 4 times the second equals 23 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #637702 by </B><A HREF=/tutors/aboutme.mpl?userid=Herdaysoji><B>Herdaysoji(25)</B></A><img src=\"/images/stars/stars-07.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Herdaysoji><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Herdaysoji><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=637702\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 3x-y=4    equ 1<BR>\n" );
document.write( "x+4y=23   equ 2<BR>\n" );
document.write( "1*  3x-y=4<BR>\n" );
document.write( "3* -3x-12y=-69<BR>\n" );
document.write( "-13y=-65<BR>\n" );
document.write( "y=5<BR>\n" );
document.write( "sub y in equ1<BR>\n" );
document.write( "3x-5=4<BR>\n" );
document.write( "3x=5+4=9<BR>\n" );
document.write( "x=9/3<BR>\n" );
document.write( "x=3 </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );