document.write( "Question 1022022: a piece of wire 80 cm long is bent to form a rectangle whose length is 3 times its width the area of rectangle thus form is? \n" ); document.write( "

Algebra.Com's Answer #637694 by josmiceli(19441) $\"\"$ $\"About$

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If the length of the rectangle is $\"+L+\"$
\n" ); document.write( "and the width is $\"+W+\"$ , then the formula
\n" ); document.write( "for circumference, $\"+C+\"$ , is:
\n" ); document.write( " $\"+C+=+2L+%2B+2W+\"$
\n" ); document.write( "given:
\n" ); document.write( " $\"+L+=+3W+\"$
\n" ); document.write( "By substitution:
\n" ); document.write( " $\"+C+=+2%2A3W+%2B+2W+\"$
\n" ); document.write( " $\"+C+=+6W+%2B+2W+\"$
\n" ); document.write( " $\"+C+=+8W+\"$
\n" ); document.write( " $\"+80+=+8W+\"$ cm
\n" ); document.write( " $\"+W+=+10+\"$
\n" ); document.write( "--------------
\n" ); document.write( " $\"+L+=+3W+\"$
\n" ); document.write( " $\"+L+=+30+\"$
\n" ); document.write( "--------------
\n" ); document.write( "Let $\"+A+\"$ = area
\n" ); document.write( " $\"+A+=+L%2AW+\"$
\n" ); document.write( " $\"+A+=+30%2A10+\"$
\n" ); document.write( " $\"+A+=+300+\"$
\n" ); document.write( "The area is 300 cm2
\n" ); document.write( "-------------------
\n" ); document.write( "check:
\n" ); document.write( " $\"+C+=+2L+%2B+2W+\"$
\n" ); document.write( " $\"+C+=+2%2A30+%2B+2%2A10+\"$
\n" ); document.write( " $\"+C+=+60+%2B+20+\"$
\n" ); document.write( " $\"+C+=+80+\"$ cm
\n" ); document.write( "OK \n" ); document.write( "

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