document.write( "Question 87904: how exactly do i get orderded pairs for the eguation it was an equation y=-x2+3x+3 then i the farthest i gotten on my formula is -3+- the square root of 21 divided by -2 \n" ); document.write( "

Algebra.Com's Answer #63769 by stanbon(75887) $\"\"$ $\"About$

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how exactly do i get ordered pairs for the eguation
\n" ); document.write( "it was an equation y=-x^2+3x+3 then i the farthest i gotten on my formula is -3+- the square root of 21 divided by -2
\n" ); document.write( "--------------
\n" ); document.write( "It looks like you were trying to apply the quadratic formula. But
\n" ); document.write( "that is not the easiest way to find ordered pairs.
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\n" ); document.write( "Getting ordered Pairs:
\n" ); document.write( "1st: pick a value for \"x\".
\n" ); document.write( "2nd: substitute that value of x into the equation to find the corresponding
\n" ); document.write( "value for y.
\n" ); document.write( "----------
\n" ); document.write( "For example:
\n" ); document.write( "If x=0, y= -0^2+4*0+3 = 3, giving you the ordered pair (0,3)
\n" ); document.write( "If x=1, y= -1^2+4*1+3 = 6, giving you the ordered pair (1,6)
\n" ); document.write( "etc.
\n" ); document.write( "=========
\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H. \n" ); document.write( "

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