document.write( "Question 1022017: y = 3x + 16
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Algebra.Com's Answer #637683 by ikleyn(52781)\"\" \"About 
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document.write( "y = 3x + 16,    (1)\r\n" );
document.write( "x = 2y - 72.    (2)\r\n" );
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document.write( "Substitute the expression y = 3x + 16 of (1) into the equation (2).\r\n" );
document.write( "You will get a single equation for x:\r\n" );
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document.write( "x = 2*(3x + 16) - 72.\r\n" );
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document.write( "Simplify and solve it.\r\n" );
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document.write( "x = 6x + 32 - 72,\r\n" );
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document.write( "5x = 40,  --->  x = \"40%2F5\" = 8  --->  y = 3x + 16 = 3*8 + 16 = 40.\r\n" );
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