document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=87901>Question 87901</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Two angles are complementary. One-half the measure of the larger angle exceeds one-fourth the measure of the smaller by 30. Find the measure of the angle, the measure of its supplement and the measure of its complement. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #63766 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=63766\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Two angles are complementary. One-half the measure of the larger angle exceeds one-fourth the measure of the smaller by 30. Find the measure of the angle, the measure of its supplement and the measure of its complement.<BR>\n" );
document.write( "-------------------------------<BR>\n" );
document.write( "Let one of the angles be \"x\"; the other is \"90-x\".<BR>\n" );
document.write( "EQUATION:<BR>\n" );
document.write( "(1/2)x = (1/4)(90-x)+30<BR>\n" );
document.write( "Multiply thru by 4 to get:<BR>\n" );
document.write( "2x = (90-x) + 120<BR>\n" );
document.write( "3x = 210<BR>\n" );
document.write( "x = 70 (measure of one of the angles)<BR>\n" );
document.write( "90-x = 20 ( measure of the other angle)<BR>\n" );
document.write( "===============<BR>\n" );
document.write( "Cheers,<BR>\n" );
document.write( "Stan H. </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );