document.write( "Question 1021907: Please help to solve this by hand.\r
\n" ); document.write( "\n" ); document.write( "ln(x/2)-ln(x-1)=ln1 \r
\n" ); document.write( "\n" ); document.write( "Workings very much appreciated, thank you.
\n" ); document.write( "Sally \n" ); document.write( "

Algebra.Com's Answer #637606 by Fombitz(32388) $\"\"$ $\"About$

You can put this solution on YOUR website!
$\"ln%28x%29-ln%282%29-ln%28x-1%29=0\"$
\n" ); document.write( " $\"ln%28x%2F%28x-1%29%29=ln%282%29\"$
\n" ); document.write( " $\"x%2F%28x-1%29=2\"$
\n" ); document.write( " $\"x=2%28x-1%29\"$
\n" ); document.write( " $\"x=2x-2\"$
\n" ); document.write( " $\"-x=-2\"$
\n" ); document.write( " $\"x=2\"$
\n" ); document.write( " \n" ); document.write( "

\n" );