document.write( "Question 1021892: The mean and standard deviation of exam score are 49% and 9% respectively.Assuming that examintion are normally distributed,calculate the probability of score:
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document.write( "A.less than 50%
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document.write( "B.more than 45%
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document.write( "C.between 52% and 63% \n" );
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Algebra.Com's Answer #637601 by Fombitz(32388) You can put this solution on YOUR website! Use the z score, \n" ); document.write( "A. \n" ); document.write( " \n" ); document.write( "B. \n" ); document.write( " \n" ); document.write( "C. \n" ); document.write( " \n" ); document.write( " |