document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1021900>Question 1021900</A>: <I><SPAN STYLE=\"word-break: break-all;\"> What is the linear equation of the line that passes through the following points -6,-2 and 6,2 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #637598 by </B><A HREF=/tutors/aboutme.mpl?userid=fractalier><B>fractalier(6550)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=fractalier><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=fractalier><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=637598\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Couple of ways to do this...we could use the two-point form, but most times students are taught to find the slope first...<BR>\n" );
document.write( "slope m = (-2 - 2)/(-6 - 6) = -4/-12 = 1/3<BR>\n" );
document.write( "Then apply y = mx + b so that, using the second point...<BR>\n" );
document.write( "2 = (1/3)(6) + b<BR>\n" );
document.write( "b = 0 so that<BR>\n" );
document.write( "y = (1/3)x is the line you want...<BR>\n" );
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