document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1021898>Question 1021898</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A rectangular painting covers an area of 12 square feet on a wall. The width of the painting is 1 foot more than its length.\r<BR>\n" );
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document.write( "Find the length and width of the painting.<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #637595 by </B><A HREF=/tutors/aboutme.mpl?userid=fractalier><B>fractalier(6550)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=fractalier><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=fractalier><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=637595\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Area A = LW = 12.<BR>\n" );
document.write( "Also we have W = L + 1.<BR>\n" );
document.write( "Substituting we have<BR>\n" );
document.write( "L(L + 1) = 12<BR>\n" );
document.write( "L^2 + L - 12 = 0<BR>\n" );
document.write( "Factoring we get<BR>\n" );
document.write( "(L + 4)(L - 3) = 0<BR>\n" );
document.write( "and the length is<BR>\n" );
document.write( "L = 3<BR>\n" );
document.write( "W = 4<BR>\n" );
document.write( "(We could have seen this from the beginning but this is the algebra for it...) </SPAN>\n" );
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