document.write( "Question 87894: Could someone help me please? The problem is:
\n" ); document.write( "A ball is thrown upward from the roof of a building 100m tall with an initial velocity of 20m/s. When will the ball reach a height of 80m?
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Algebra.Com's Answer #63759 by Earlsdon(6294)\"\" \"About 
You can put this solution on YOUR website!
Well, you can start with the function that gives the height, as a function of time, h(t) of an object propelled upward with an initial upward velocity of \"v%5B0%5D%5D%5D\"m/s from an initial height of \"h%5B0%5D\"m.
\n" ); document.write( "\"h%28t%29+=+-4.9t%5E2%2Bv%5B0%5Dt%2Bh%5B0%5D\"
\n" ); document.write( "In this problem:
\n" ); document.write( "\"h%5B0%5D+=+100\"m.
\n" ); document.write( "\"v%5B0%5D+=+20\"m/s.
\n" ); document.write( "You would like to know at what time, t, will h = 80 meters.
\n" ); document.write( "Making the appropriate substitutions into the formula:
\n" ); document.write( "\"80+=+-4.9t%5E2%2B20t%2B100\" Subtract 80 from both sides.
\n" ); document.write( "\"-4.9t%5E2%2B20t%2B20+=+0\" Solve this quadratic equation using the quadratic formula: \"t+=+%28-b%2B-sqrt%28b%5E2-4ac%29%29%2F2a\" In this equation, a = -4.9, b = 20, and c = 20
\n" ); document.write( "\"t+=+%28-20%2B-sqrt%2820%5E2-4%28-4.9%29%2820%29%29%29%2F2%28-4.9%29\" Simplifying this, you'll get:
\n" ); document.write( "\"t+=+%28-20%2B-sqrt%28400-%28-392%29%29%29%2F-9.8\"
\n" ); document.write( "\"t+=+%28-20%2B-sqrt%28792%29%29%2F-9.8\" Evaluating this gets you:
\n" ); document.write( "\"t+=+4.912499\" or \"t+=+-0.830866\" Discard the negative solution.
\n" ); document.write( "\"t+=+4.9\"seconds.
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