document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1021832>Question 1021832</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Find three consecutive odd integer such that 2 times the sum of the first two numbers is one less than thrice the third number.<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #637560 by </B><A HREF=/tutors/aboutme.mpl?userid=addingup><B>addingup(3677)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=addingup><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=addingup><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=637560\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Odd integers. 1, 3, 5, etc. The difference between them is 2 (1+2=3, 3+2 = 5, etc)<BR>\n" );
document.write( "So, our numbers are going to be:<BR>\n" );
document.write( "x, x+2, x+2+2 = x, x+2, x+4<BR>\n" );
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document.write( "2(x+x+2)= 3(x+4)-1 Multiply to get rid of parenthesis<BR>\n" );
document.write( "2x+2x+4 =  3x+12-1 Add<BR>\n" );
document.write( "4x+4 = 3x+11 Subtract 4 and 3x on both sides<BR>\n" );
document.write( "x = 7 This is our first number.<BR>\n" );
document.write( "Second number: 7+2 = 9<BR>\n" );
document.write( "Third number: 9+2 = 11 <BR>\n" );
document.write( "Now let's check by plugging these number into the equation and finding out if we have the right answer. The problem says:<BR>\n" );
document.write( "2(7+9) = 3(11)-1<BR>\n" );
document.write( "32 = 32 We have the correct answer.<BR>\n" );
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