document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=87816>Question 87816</A>: <I><SPAN STYLE=\"word-break: break-all;\">   	 The perimeter of an equilateral triangle is 18. Find the measure of the altitude. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #63754 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley75><B>checkley75(3666)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley75><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=63754\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> AN EQUILATERAL TRIANGLE HAS THREE EQUAL SIDES. tHUS 18/3=6 IS THE LENGTH OF EACH SIDE.<BR>\n" );
document.write( "THE ALTITUDE CUTS THE BASE IN HALF SO NOW WE HAVE A RIGHT TRIANGLE WITH THE BASE=3 & THE HYPOTENUSE=6. <BR>\n" );
document.write( "NOW WE SOLVE FOR THE ALTITUDE.<BR>\n" );
document.write( "3^2+A^2=6^2<BR>\n" );
document.write( "9+A^2=36<BR>\n" );
document.write( "A^2=36-9<BR>\n" );
document.write( "A^2=36-9<BR>\n" );
document.write( "A^2=27<BR>\n" );
document.write( "A=SQRT27<BR>\n" );
document.write( "A=5.196 ANSWER.<BR>\n" );
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