document.write( "Question 1021838: Hi im having so much trouble proving this formula with mathematical induction.
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\n" ); document.write( "\n" ); document.write( "\"+1%2F%281%2A3%29%2B1%2F%283%2A5%29\"+...+\"%2B1%2F%28%282n-1%29%282n%2B1%29%29=n%2F%282n%2B1%29+\"\r
\n" ); document.write( "\n" ); document.write( "Basis step: n=1 was true
\n" ); document.write( "Assumption step: n=k
\n" ); document.write( "\"%2B1%2F%28%282k-1%29%282k%2B1%29%29=k%2F%282k%2B1%29+\"
\n" ); document.write( "Induction step: Prove true for n=(k+1)
\n" ); document.write( "\"+1%2F%281%2A3%29%2B1%2F%283%2A5%29\"+...+\"%2B1%2F%28%282k-1%29%282k%2B1%29%29\"+
\n" ); document.write( "\"+1%2F%281%2A3%29%2B1%2F%283%2A5%29\"+...+\"k%2F%282k%2B1%29+\"+\"%2B1%2F%28%282k%2B1%29%282k%2B3%29%29=%28k%2B1%29%2F%282k%2B3%29+\"\r
\n" ); document.write( "\n" ); document.write( "From here I have no idea what to do, to the LHS to make it equal to RHS\r
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Algebra.Com's Answer #637534 by robertb(5830)\"\" \"About 
You can put this solution on YOUR website!
The assumption of induction is:\r
\n" ); document.write( "\n" ); document.write( "\"1%2F%281%2A3%29%2B+1%2F%283%2A5%29\"+...+\"1%2F%28%282k-1%29%282k%2B1%29%29=k%2F%282k%2B1%29+\"\r
\n" ); document.write( "\n" ); document.write( "Now add \"1%2F%28%282k%2B1%29%282k%2B3%29%29\" to BOTH sides.\r
\n" ); document.write( "\n" ); document.write( "==> \"1%2F%281%2A3%29%2B+1%2F%283%2A5%29\"+...+\r
\n" ); document.write( "\n" ); document.write( "(Note: 1) The last equation is TRUE by the induction hypothesis. 2) We added 1/(2k+1)(2k+3) because it is supposed to be the next term in line after 1/(2k-1)(2k+1).)\r
\n" ); document.write( "\n" ); document.write( "The RHS of the last equation is equal to \r
\n" ); document.write( "\n" ); document.write( "\"%28k%282k%2B3%29%29%2F%28%282k%2B1%29%282k%2B3%29%29+%2B+1%2F%28%282k%2B1%29%282k%2B3%29%29\"\r
\n" ); document.write( "\n" ); document.write( "=\"%282k%5E2%2B3k%2B1%29%2F%28%282k%2B1%29%282k%2B3%29%29\"
\n" ); document.write( "=\"%28%282k%2B1%29%28k%2B1%29%29%2F%28%282k%2B1%29%282k%2B3%29%29\" = \"%28k%2B1%29%2F%282k%2B3%29\"\r
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\n" ); document.write( "\n" ); document.write( "I leave the rest of the inductive argument to you...
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