document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1021834>Question 1021834</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Ans please with Solution..\r<BR>\n" );
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document.write( "A farmer uses 140 feet of fencing to enclose a rectangular field, If the length of the field is (33)1/3% greater than its width .What is the diagonal distance from one corner of the enclosure to the opposite corner? <BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #637532 by </B><A HREF=/tutors/aboutme.mpl?userid=rothauserc><B>rothauserc(4718)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=rothauserc><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=rothauserc><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=637532\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 33 and (1/3)% = 33 and (1/3) / 100 = (33 and 1/3 / 100) * (3/3) = 100 / 300 = 1/3<BR>\n" );
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document.write( "length = width(w) + (w/3)<BR>\n" );
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document.write( "perimeter(P) = 2w + 2(4w/3)<BR>\n" );
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document.write( "140 = 2w + 8w/3<BR>\n" );
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document.write( "14w/3 = 140<BR>\n" );
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document.write( "14w = 560<BR>\n" );
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document.write( "w = 40 and l = 160/3<BR>\n" );
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document.write( "use Pythagorean Theorem to find the length of the diagonal<BR>\n" );
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document.write( "(120/3)^2 + (160/3)^2 = d^2<BR>\n" );
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document.write( "d^2 =  40000 / 9<BR>\n" );
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document.write( "d = square root (40000 / 9) = 200 / 3 = 66 and (2/3) feet<BR>\n" );
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document.write( "the diagonal is 66 and (2/3) feet long<BR>\n" );
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