document.write( "Question 1021776: Hey, my name is Charity. Can you please help me on this problem>>\r
\n" );
document.write( "\n" );
document.write( "Two hamburgers and a coke cost $5.10. Three hamburgers and two cokes cost $8.40. Let h= cost of hamburgers and c= cost of a coke\r
\n" );
document.write( "\n" );
document.write( "Thanks in advance :) \n" );
document.write( "
Algebra.Com's Answer #637494 by macston(5194)![]() ![]() You can put this solution on YOUR website! . \n" ); document.write( "2H+C=$5.10 \n" ); document.write( "C=$5.10-2H . Use this to substitute for C below. \n" ); document.write( ". \n" ); document.write( "3H+2C=$8.40 . Substitute for C from above. \n" ); document.write( "3H+2($5.10-2H)=$8.40 \n" ); document.write( "3H+$10.20-4H=$8.40 \n" ); document.write( "-H=-$1.80 \n" ); document.write( "H=$1.80 \n" ); document.write( ". \n" ); document.write( "C=$5.10-2H=$5.10-2($1.80)=$5.10-$3.60=$1.50 \n" ); document.write( ". \n" ); document.write( "ANSWER: Hamburgers cost $1.80 and cokes cost $1.50. \n" ); document.write( ". \n" ); document.write( "CHECK: \n" ); document.write( ". \n" ); document.write( "2H+C=$5.10 \n" ); document.write( "2($1.80)+$1.50=$5.10 \n" ); document.write( "$3.60+$1.50=$5.10 \n" ); document.write( "$5.10=$5.10 \n" ); document.write( ". \n" ); document.write( "3H+2C=$8.40 \n" ); document.write( "3($1.80)+2($1.50)=$8.40 \n" ); document.write( "$5.40+$3.00=$8.40 \n" ); document.write( "$8.40=$8.40 \n" ); document.write( ". \n" ); document.write( " \n" ); document.write( " |