document.write( "Question 1021743: Ellen wishes to mix candy worth $1.23 per pound with candy worth $3.36 per pound to form 15 pounds of a mixture worth $2.37 per pound. How many pounds of the more expensive candy should she use? \n" ); document.write( "
Algebra.Com's Answer #637475 by macston(5194)\"\" \"About 
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\n" ); document.write( "x=pounds of less expensive candy; y=pounds of more expensive candy
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\n" ); document.write( "x+y=15
\n" ); document.write( "x=15-y . Use this to substitute for x below.
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\n" ); document.write( "$1.23x+$3.36y=$2.37(15) . Substitute for x from above.
\n" ); document.write( "$1.23(15-y)+$3.36y=$35.55
\n" ); document.write( "$18.45-$1.23y+$3.36y=$35.55
\n" ); document.write( "$2.13y=$17.10
\n" ); document.write( "y=8.03
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\n" ); document.write( "x=15-y=15-8.03=6.97
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\n" ); document.write( "ANSWER: She should use 6.97 pounds of the less expensive candy and 8.03 pounds of the more expensive candy.
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\n" ); document.write( "CHECK:
\n" ); document.write( ".
\n" ); document.write( "$1.23x+$3.36y=$2.37(15)
\n" ); document.write( "$1.23x+$3.36y=$35.55
\n" ); document.write( "$1.23(6.97)+$3.36(8.03)=$35.55
\n" ); document.write( "$8.57+$26.98=$35.55
\n" ); document.write( "$35.55=$35.55
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