document.write( "Question 1021569: A construction firm was hired to repaint a very large bridge. Written into the contract was a $2 million penalty if the bridge was not completed in 87 days; Their crew of 7 painted 1/3 of the bridge in 45 days. How many more painters should be hired to allow the crew to paint the rest of the bridge in the 42 remaining days?\r
\n" ); document.write( "\n" ); document.write( "-The class calculated that if 7 crew members painted 1/3 of the bridge in 45 days, then (1/3 bridge / 7 members) = 1/21 per crew member...
\n" ); document.write( "BUT: I wasn't sure what to do with that information, though.\r
\n" ); document.write( "\n" ); document.write( "Can you help me understand how to get to the solution? Thank you in advance.\r
\n" ); document.write( "\n" ); document.write( "-Mark
\n" ); document.write( "Mark.ed.wells@gmail.com
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Algebra.Com's Answer #637461 by macston(5194)\"\" \"About 
You can put this solution on YOUR website!
(1/21 per member)/(45 days)=1/945 bridge per man per day
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\n" ); document.write( "2/3 bridge is 630/945 of the bridge:
\n" ); document.write( "At 1/945 bridge per man-day, we need 630 man-days in 42 days
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\n" ); document.write( "630 man-days/42 days=15 men.
\n" ); document.write( "We need 15 painters to finish in time, and we have 7 men,
\n" ); document.write( "so we need 8 additional men.
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