document.write( "Question 1021679: A box contains $6.60 in nickels, dimes and quarters. There are three times as many nickels as quarters, and the number of dimes is 4 less than the number of nickels. How many of each coin are there? \n" ); document.write( "
Algebra.Com's Answer #637429 by macston(5194)\"\" \"About 
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\n" ); document.write( "N=nickels; Q=quarters=(1/3)N; D=dimes=N-4
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\n" ); document.write( "$0.05N+$0.10D+$0.25Q=$6.60
\n" ); document.write( "$0.05N+$0.10(N-4)+$0.25((1/3)N)=$6.60
\n" ); document.write( "$0.05N+$0.10N-$0.40+($0.25/3)N=$6.60
\n" ); document.write( "$0.15N+($0.25/3)N=$7.00
\n" ); document.write( "($0.45/3)N+($0.25/3)N=$7.00
\n" ); document.write( "($0.70/3)N=$7.00
\n" ); document.write( "$0.70N=$21.00
\n" ); document.write( "N=30
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\n" ); document.write( "Q=(1/3)N=(1/3)(30)=10
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\n" ); document.write( "D=N-4=30-4=26
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\n" ); document.write( "ANSWER: There are 30 nickels, 26 dimes, and 10 quarters.
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\n" ); document.write( "CHECK:
\n" ); document.write( "$0.05N+$0.10D+$0.25Q=$6.60
\n" ); document.write( "$0.05(30)+$0.10(26)+$0.25(10)=$6.60
\n" ); document.write( "$1.50+$2.60+$2.50=$6.60
\n" ); document.write( "$6.60=$6.60
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