document.write( "Question 1021681: How much of an alloy that is 30% copper should be mixed with 400 ounces of an alloy that is 90% copper in order to get an alloy that is 70%? \n" ); document.write( "
Algebra.Com's Answer #637425 by macston(5194)\"\" \"About 
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\n" ); document.write( "T=amount of 30% alloy
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\n" ); document.write( "0.30T+0.90(400)=0.70(T+400)
\n" ); document.write( "0.30T+360=0.70T+280
\n" ); document.write( "80=0.40T
\n" ); document.write( "200=T
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\n" ); document.write( "ANSWER: 200 ounces of 30% alloy should be used.
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