document.write( "Question 1021681: How much of an alloy that is 30% copper should be mixed with 400 ounces of an alloy that is 90% copper in order to get an alloy that is 70%? \n" ); document.write( "
Algebra.Com's Answer #637425 by macston(5194)![]() ![]() You can put this solution on YOUR website! . \n" ); document.write( "T=amount of 30% alloy \n" ); document.write( ". \n" ); document.write( "0.30T+0.90(400)=0.70(T+400) \n" ); document.write( "0.30T+360=0.70T+280 \n" ); document.write( "80=0.40T \n" ); document.write( "200=T \n" ); document.write( ". \n" ); document.write( "ANSWER: 200 ounces of 30% alloy should be used. \n" ); document.write( ". \n" ); document.write( " \n" ); document.write( " |