document.write( "Question 1021512: Please solve and explain 2x^2-6>11 \n" ); document.write( "

Algebra.Com's Answer #637336 by Fombitz(32388) $\"\"$ $\"About$

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$\"2x%5E2-17%3E0\"$
\n" ); document.write( "So now you want to graph the function and look for the region where the function is greater than zero (above the x-axis).
\n" ); document.write( "You can solve for when the function equals zero first.
\n" ); document.write( " $\"2x%5E2=17\"$
\n" ); document.write( " $\"x%5E2=%2817%2F2%29\"$
\n" ); document.write( " $\"x=0+%2B-+sqrt%2817%2F2%29%7D%7D%0D%0A%7B%7B%7Bx=0+%2B-+sqrt%2834%29%2F2%29\"$
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\n" ); document.write( "So now choose a point in between the zeros and check whether the function is above or below the x-axis at that point.
\n" ); document.write( " $\"x=0\"$ is convenient.
\n" ); document.write( " $\"2%280%29%5E2-6%3E11\"$
\n" ); document.write( " $\"-6%3E11\"$
\n" ); document.write( "False, so in between the zeros the function is not greater than zero.
\n" ); document.write( "So the other regions are the where the function is greater than zero.
\n" ); document.write( "( $\"-infinity\"$ , $\"-sqrt%2834%29%2F2\"$ )U( $\"sqrt%2834%29%2F2\"$ , $\"infinity\"$ )
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