document.write( "Question 1021583: A computer repair person is ‘beeped’ each time there is a call for service. The number of beeps per hour has a Poisson distribution with mean 2 beeps per hour. Calculate the probability that there will be: \r
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document.write( "i. At least two beeps in an hour.
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document.write( "ii. One beep in next three hours.
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document.write( "iii. No beep in 45 minutes.
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Algebra.Com's Answer #637314 by robertb(5830)![]() ![]() You can put this solution on YOUR website! We use the pmf of Poisson r.v.\r \n" ); document.write( "\n" ); document.write( "i. \n" ); document.write( "The answer is p(2)+p(3)+p(4) +... = 1 - p(0) - p(1) = \n" ); document.write( "\n" ); document.write( "ii. Here \n" ); document.write( "==> \n" ); document.write( "\n" ); document.write( "iii. Here \n" ); document.write( "==> \n" ); document.write( " \n" ); document.write( " |