document.write( "Question 1021478: 13>3+2x \n" ); document.write( "

Algebra.Com's Answer #637237 by ankor@dixie-net.com(22740) $\"\"$ $\"About$

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13 > 3 + 2x
\n" ); document.write( "we can rewrite this to
\n" ); document.write( "3 + 2x < 13
\n" ); document.write( "2x < 13 - 3
\n" ); document.write( "2x < 10
\n" ); document.write( "x < 10/2
\n" ); document.write( "x < 5
\n" ); document.write( ":
\n" ); document.write( "Check this in the original problem; x is less than 5, check it with x=4
\n" ); document.write( "13 > 3 + 2(4)
\n" ); document.write( "13 > 11, which is true \n" ); document.write( "

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