document.write( "Question 1021347: Hello, thanks for spending time to help. Here is the question:\r
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document.write( "Jack bought some erasers, pencils, and rulers. 1/6 of them were erasers. The number of pencils he bought was 5 more than 1/2 the total number of all items and the remaining were rulers. Each of the erasers, pencils and rulers costs $2.20, $3.45 and $1.70 respectively. He spent a total of $519.15 on all the items. How many more pencils than erasers did Jack buy ? \n" );
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Algebra.Com's Answer #637229 by rothauserc(4718) You can put this solution on YOUR website! let e + p + r = t where e is number of erasers, p is number of pencils, r is number of rulers and t is the total number, then \n" ); document.write( "e = (1/6)t \n" ); document.write( "p = (1/2)t + 5 \n" ); document.write( "r = t - ((1/6)t + (1/2)t + 5) \n" ); document.write( ": \n" ); document.write( "2.20(t/6) + 3.45(t/2 +5) + 1.70(t - t/6 - t/2 - 5) = 519.15 \n" ); document.write( ": \n" ); document.write( "(2.20t/6) + 3.45t/2 +17.25 + 1.70t - 1.70t/6 - 1.70t/2 -8.50 = 519.15 \n" ); document.write( ": \n" ); document.write( "multiply both sides of = by 6 \n" ); document.write( "2.20t +10.35t +103.5 +10.20t -1.70t -5.10t -51.00 = 3114.9 \n" ); document.write( ": \n" ); document.write( "15.95t = 3062.4 \n" ); document.write( ": \n" ); document.write( "t = 192 \n" ); document.write( ": \n" ); document.write( "********************************************************** \n" ); document.write( "The total items bought is 192 \n" ); document.write( "The number of erasers bought is 32 \n" ); document.write( "The number of pencils bought is 101 \n" ); document.write( "The number of rulers bought is (192 - 133) = 59 \n" ); document.write( "Therefore, \n" ); document.write( "There were (101 - 32) = 69 more pencils bought than erasers \n" ); document.write( "*********************************************************** \n" ); document.write( " \n" ); document.write( " |