document.write( "Question 1021421: Write the equation -2x + 6y = 9 in polar form.
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document.write( "9sqrt(10)/20 = r cos (theta - 108)
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document.write( "9sqrt(10)/20 = r cos (theta - 72)
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document.write( "7sqrt(10)/20 = r cos (theta - 108)
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document.write( "7sqrt(10)/20 = r cos (theta - 72)\r
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document.write( "I'm really stuck here so any help would be very much appreciated, thanks! \n" );
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Algebra.Com's Answer #637220 by rothauserc(4718)![]() ![]() You can put this solution on YOUR website! -2x +6y = 9 \n" ); document.write( ": \n" ); document.write( "standard form is \n" ); document.write( ": \n" ); document.write( "-2x +6y -9 = 0 then \n" ); document.write( "2x -6y +9 = 0 \n" ); document.write( ": \n" ); document.write( "A=2, B=-6, C=9 \n" ); document.write( ": \n" ); document.write( "+ or - square root(4+36) = + or - 2square root(10) \n" ); document.write( ": \n" ); document.write( "use -2square root(10), the minus is opposite sign of C \n" ); document.write( ": \n" ); document.write( "(2x /(-2square root(10)) -6y/(-2square root(10)) +(9 / (-2square root(10)) = 0 \n" ); document.write( ": \n" ); document.write( "multiply the numerator and denominator of each fraction by square root(10) \n" ); document.write( ": \n" ); document.write( "(-2square root(10) / 20)x +(6square root(10) / 20)y -(9square root(10) / 20) = 0 \n" ); document.write( ": \n" ); document.write( "note that -cos, +sin implies quadrant II \n" ); document.write( ": \n" ); document.write( "phi = cos^(-1) of (-2square root(10) / 20) = 108.434948822 \n" ); document.write( ": \n" ); document.write( "********************************************************** \n" ); document.write( "correct answer is \n" ); document.write( "(9 * square root(10) / 20) = r * cos(theta - 108) \n" ); document.write( ": \n" ); document.write( "note that * means multiply \n" ); document.write( "********************************************************* \n" ); document.write( " |