document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1021367>Question 1021367</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Half of isha's age added to twice of majue's age total 70 years.in 5 years time their age added up to 75 years how old are they. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #637210 by </B><A HREF=/tutors/aboutme.mpl?userid=fractalier><B>fractalier(6550)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=fractalier><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=fractalier><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=637210\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Call isha's age and majue's age NOW, x and y.  Then we can write<BR>\n" );
document.write( "(1/2)x + 2y = 70  (let's multiply by two) and get<BR>\n" );
document.write( "x + 4y = 140<BR>\n" );
document.write( "In 5 years,<BR>\n" );
document.write( "(x+5) + (y+5) = 75  or<BR>\n" );
document.write( "x + y + 10 = 75  and<BR>\n" );
document.write( "x + y = 65<BR>\n" );
document.write( "Subtract this from the above and get<BR>\n" );
document.write( "x + 4y = 140<BR>\n" );
document.write( "-(x + y = 65)<BR>\n" );
document.write( "---------------<BR>\n" );
document.write( "3y = 75<BR>\n" );
document.write( "y = 25<BR>\n" );
document.write( "and then<BR>\n" );
document.write( "x = 40 </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );