document.write( "Question 1021384: Mrs. Jackson is 2 years more than 3 times as old as her son. If the difference between their ages is 22 years, how old is Mrs. Jackson? \n" ); document.write( "
Algebra.Com's Answer #637203 by macston(5194)![]() ![]() You can put this solution on YOUR website! . \n" ); document.write( "J=Mrs. Jackson's age; S=son's age \n" ); document.write( ". \n" ); document.write( "J-S=22yrs \n" ); document.write( "J=S+22yrs \n" ); document.write( ". \n" ); document.write( "J=3S+2yrs \n" ); document.write( "S+22yrs=3S+2yrs \n" ); document.write( "20yrs=2S \n" ); document.write( "10yrs=S \n" ); document.write( ". \n" ); document.write( "The son is 10 years old. \n" ); document.write( ". \n" ); document.write( "J=S+22yrs=10yrs+22yrs=32yrs \n" ); document.write( ". \n" ); document.write( "ANSWER: Mrs. Jackson is 32 years old \n" ); document.write( ".\r \n" ); document.write( "\n" ); document.write( "CHECK: \n" ); document.write( ". \n" ); document.write( "J=3S+2yrs \n" ); document.write( "32 yrs=3(10yrs)+2yrs \n" ); document.write( "32yrs=30yrs+2yrs \n" ); document.write( "32yrs=32yrs \n" ); document.write( ". \n" ); document.write( " \n" ); document.write( " |