document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1021402>Question 1021402</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Diego and Ken both leave the mall at the same time, but in opposite directions. If Ken travels 4 mph faster than Diego and after 6 hours they are 180 miles apart, how fast is each traveling?<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #637116 by </B><A HREF=/tutors/aboutme.mpl?userid=fractalier><B>fractalier(6550)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=fractalier><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=fractalier><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=637116\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Couple of ways to do this...<BR>\n" );
document.write( "If they covered 180 miles between them, in 6 hours, then their combined rate was<BR>\n" );
document.write( "180 miles / 6 hours = 30 miles per hour<BR>\n" );
document.write( "Call Diego's rate, x.<BR>\n" );
document.write( "Then Ken's rate is x+4.<BR>\n" );
document.write( "Together they add to 30...<BR>\n" );
document.write( "x + x+4 = 30<BR>\n" );
document.write( "2x + 4 = 30<BR>\n" );
document.write( "2x = 26<BR>\n" );
document.write( "x = 13 mph<BR>\n" );
document.write( "x+4 = 17 mph </SPAN>\n" );
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