document.write( "Question 87823: I really need help on this one because I am really bad at graphing.
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document.write( "The problem goes like this: Solve and graph the solution set--
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document.write( "a) |4q-18|_>0
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document.write( "b) 12-|7-2m|= 9
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document.write( "c) |r+5|+3_<3
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document.write( "PLEASE HELP ME!!!!!!!!!!!!! \n" );
document.write( "
Algebra.Com's Answer #63709 by Edwin McCravy(20056)![]() ![]() You can put this solution on YOUR website! \r\n" ); document.write( "I really need help on this one because I am really bad at graphing.\r\n" ); document.write( "The problem goes like this: Solve and graph the solution set--\r\n" ); document.write( "a) |4q - 18| > 0\r\n" ); document.write( "\r\n" ); document.write( "This is one which you do not do any work on, you just reason it out\r\n" ); document.write( "this way. Every absolute value of every number is always a number\r\n" ); document.write( "which is NEVER negative, but always either ZERO or POSITIVE. But\r\n" ); document.write( "that's exactly what \"greater than or equal to ZERO\" means. So\r\n" ); document.write( "the solution set is \"ALL REAL NUMBERS\", which in interval notation is\r\n" ); document.write( "(-oo, oo)\r\n" ); document.write( "\r\n" ); document.write( "b) 12 - |7 - 2m| = 9\r\n" ); document.write( "\r\n" ); document.write( "We add -12 to both sides\r\n" ); document.write( "\r\n" ); document.write( " -|7 - 2m| = 9 - 12\r\n" ); document.write( "\r\n" ); document.write( " -|7 - 2m| = -3\r\n" ); document.write( "\r\n" ); document.write( "Multiply both sides by -1\r\n" ); document.write( "\r\n" ); document.write( " |7 - 2m| = 3\r\n" ); document.write( "\r\n" ); document.write( "To get rid of the absolute values,\r\n" ); document.write( "break this into two separate\r\n" ); document.write( "equations, and solve EACH:\r\n" ); document.write( "\r\n" ); document.write( " 7 - 2m = 3 OR 7 - 2m = -3\r\n" ); document.write( " -2m = -4 OR -2m = -10\r\n" ); document.write( " m = 2 OR m = 5\r\n" ); document.write( "\r\n" ); document.write( "Those are the two solutions. \r\n" ); document.write( "\r\n" ); document.write( "c) |r + 5| + 3 < 3\r\n" ); document.write( "\r\n" ); document.write( " Subtract 3 from both sides\r\n" ); document.write( "\r\n" ); document.write( " |r + 5| < 0\r\n" ); document.write( "\r\n" ); document.write( "This is another one which you do not do like the others. You reason \r\n" ); document.write( "it out this way. Every absolute value of every number is always a \r\n" ); document.write( "number which is NEVER negative, but always either ZERO or POSITIVE. But\r\n" ); document.write( "\"less than or equal to ZERO\" means \"ZERO or negative\". Since the \r\n" ); document.write( "absiolute value |r + 5| can never be negative, then it can only be \r\n" ); document.write( "ZERO, so \r\n" ); document.write( " |r + 5| = 0\r\n" ); document.write( "\r\n" ); document.write( "Or r + 5 = 0\r\n" ); document.write( " r = -5\r\n" ); document.write( "\r\n" ); document.write( "That is the only solution.\r\n" ); document.write( "\r\n" ); document.write( "Edwin \n" ); document.write( " \n" ); document.write( " |