document.write( "Question 1021264: if x and y are odd numbers, then x+y is even\r
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document.write( "If x and y are both odd, then x+1 and y-1 are even. But then x+y=(x+1)+(y-1) is the sum of two even numbers, and, therefore, even.\r
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document.write( "Is this a valid proof? If so, what type of proof is it because I am confused. \n" );
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Algebra.Com's Answer #637022 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! if x and y are odd numbers, then x+y is even:: True \n" ); document.write( "----------------------------------------------- \n" ); document.write( "If x and y are both odd, then x+1 and y-1 are even.:: True \n" ); document.write( "----------------------------------------------- \n" ); document.write( " But then x+y=(x+1)+(y-1) is the sum of two even numbers \n" ); document.write( " and, therefore, even:: \n" ); document.write( "Is this a valid proof? If so, what type of proof is it because I am confused. \n" ); document.write( "------ \n" ); document.write( "It shows that \"if x and y are odd, the sum of x+1 and y-1 is even. \n" ); document.write( "------ \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( "----------- \n" ); document.write( " \n" ); document.write( " |