document.write( "Question 1021264: if x and y are odd numbers, then x+y is even\r
\n" ); document.write( "\n" ); document.write( "If x and y are both odd, then x+1 and y-1 are even. But then x+y=(x+1)+(y-1) is the sum of two even numbers, and, therefore, even.\r
\n" ); document.write( "\n" ); document.write( "Is this a valid proof? If so, what type of proof is it because I am confused.
\n" ); document.write( "

Algebra.Com's Answer #637022 by stanbon(75887)\"\" \"About 
You can put this solution on YOUR website!
if x and y are odd numbers, then x+y is even:: True
\n" ); document.write( "-----------------------------------------------
\n" ); document.write( "If x and y are both odd, then x+1 and y-1 are even.:: True
\n" ); document.write( "-----------------------------------------------
\n" ); document.write( " But then x+y=(x+1)+(y-1) is the sum of two even numbers
\n" ); document.write( " and, therefore, even::
\n" ); document.write( "Is this a valid proof? If so, what type of proof is it because I am confused.
\n" ); document.write( "------
\n" ); document.write( "It shows that \"if x and y are odd, the sum of x+1 and y-1 is even.
\n" ); document.write( "------
\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
\n" ); document.write( "-----------
\n" ); document.write( "
\n" ); document.write( "
\n" );