document.write( "Question 1021214: f is a continuous function with a domain [−3, 9] such that
\n" ); document.write( "f of x equals 3 for x between negative 3 and 0 including negative 3, equals negative 1 times x plus 3 for x between 0 and 6 inclusive, and equals negative 3 for x greater than 6 and less than or equal to 9
\n" ); document.write( "and let g of x equals the integral from negative 2 to x of f of t, dt.
\n" ); document.write( "1. On what interval is g increasing? Justify your answer. \r
\n" ); document.write( "\n" ); document.write( "2. For 0 ≤ x ≤ 6, express g(x) in terms of x. Do not include +C in your final answer.
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Algebra.Com's Answer #636990 by Fombitz(32388)\"\" \"About 
You can put this solution on YOUR website!
a) g increases from [-3,3]. From the graph the function f cross the x axis and the total area starts decreasing.
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\n" ); document.write( "b) Break up the integral into 3 regions.
\n" ); document.write( "[-3,0]
\n" ); document.write( "\"g%5B1%5D%28x%29=int%28%283%29%2Cdx%2C-3%2Cx%29\"
\n" ); document.write( "\"g%5B1%5D%28x%29=3x%2B9\"
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\n" ); document.write( "[0,6]
\n" ); document.write( "\"g%5B2%5D%28x%29=g%5B1%5D%280%29%2Bint%28%28-x%2B3%29%2Cdx%2C0%2Cx%29\"
\n" ); document.write( "\"g%5B2%5D%28x%29=9-x%5E2%2F3%2B3x\"
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\n" ); document.write( "[6,9]
\n" ); document.write( "\"g%5B3%5D%28x%29=g%5B2%5D%286%29%2Bint%28%28-3%29%2Cdx%2C6%2Cx%29\"
\n" ); document.write( "\"g%5B3%5D%28x%29=9-3%28x-6%29\"
\n" ); document.write( "\"g%5B3%5D%28x%29=27-3x\"
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