document.write( "Question 1021014: The intensity I of light from a light bulb varies inversely as the square of the distance d from the light bulb. Suppose I is 810 w/m^2 when the distance is 3 m. How much farther would it be to a point where the intensity is 160 w/m^2. \n" ); document.write( "
Algebra.Com's Answer #636925 by Theo(13342)![]() ![]() You can put this solution on YOUR website! The intensity I of light from a light bulb varies inversely as the square of the distance d from the light bulb. Suppose I is 810 w/m^2 when the distance is 3 m. How much farther would it be to a point where the intensity is 160 w/m^2.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "the formula is i = k / d^2\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "i equals the intensity of the light in watts per square meter. \n" ); document.write( "d equals the distances from the light bulb in meters. \n" ); document.write( "k is the constant of variation.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "i is 810 watts per square meter when d is 3 meters.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "the formula if i = k / d^2 becomes 810 = k / 3^2.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "this becomes 810 = k / 9.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "solve for k to get k = 810 * 9 = 7290.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "you are asked to determine how much farther away from the light bulb would a point be if the intensity of the light was 160 watts per square meter.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "k is the constant of variation, so it stays the same.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "the formula of i = k / d^2 becomes i = 7290 / d^2.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "when i = 160, the formula becomes 160 = 7290 / d^2.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "solve for d^2 to get d^2 = 7290 / 160 = 45.5625.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "solve for d to get d = sqrt(45.5625) = 6.75 meters.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "the intensity of light would be 160 watts per square meter when the distance from the light bulb is 6.75 meters.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "that would be 6.75 - 3 = 3.75 meters further away.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "that's your solution.\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |