document.write( "Question 1021071: A $100,000 house appreciates at a rate of $3500 a year.
\n" ); document.write( "a.Find the equation that models the value of the house in y dollars after x years.
\n" ); document.write( "b.Find the value of the house in 12 years.
\n" ); document.write( "c.How many years from now will the value of the house be $124,500? \r
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Algebra.Com's Answer #636917 by Cromlix(4381)\"\" \"About 
You can put this solution on YOUR website!
Hi there,
\n" ); document.write( "3500/100,000 x 100 = 3.5%
\n" ); document.write( "3.5% appreciation = 100 + 3.5
\n" ); document.write( "= 103.5% = 1.035/100 = 1.035
\n" ); document.write( "a) y x 1.035^x
\n" ); document.write( "b) $100,000 x 1.035^12
\n" ); document.write( " $151,106.87.
\n" ); document.write( "c) $124,500 = 100,000 x 1.035^x
\n" ); document.write( "124,500/100,000 = 1.035^x
\n" ); document.write( "1.245 = 1.035^x
\n" ); document.write( "log 1.245 = x log1.035
\n" ); document.write( "x = log 1.245/log 1.035
\n" ); document.write( "x = 6.37 years
\n" ); document.write( "Hope this helps :-)
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