document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1020990>Question 1020990</A>: <I><SPAN STYLE=\"word-break: break-all;\"> You measure the shadow cast by a certain tall building and find it to be 85 feet long. Then you measure the shadow cast by a three-foot post and find it to be 4 inches long. Determine the building's height. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #636909 by </B><A HREF=/tutors/aboutme.mpl?userid=Cromlix><B>Cromlix(4381)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Cromlix><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Cromlix><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=636909\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Hi there,<BR>\n" );
document.write( "Consider the post and its shadow as a right<BR>\n" );
document.write( "angled triangle.<BR>\n" );
document.write( "The post is the opposite side<BR>\n" );
document.write( "The shadow is the adjacent side.<BR>\n" );
document.write( "Using trigonometric ratios<BR>\n" );
document.write( "tan(x) = opposite/adjacent<BR>\n" );
document.write( "tan(x) = 36 inches/4 inches<BR>\n" );
document.write( "tan(x) = 9<BR>\n" );
document.write( "x = 83.66 degrees.<BR>\n" );
document.write( "Now consider the building.<BR>\n" );
document.write( "The building is the opposite side.<BR>\n" );
document.write( "Its shadow is the adjacent side<BR>\n" );
document.write( "tan(83.66) = opposite/1020 inches<BR>\n" );
document.write( "Opposite = 1020 inches x tan(83.66)<BR>\n" );
document.write( "Opposite = 9180.28 inches<BR>\n" );
document.write( "= 765 feet.<BR>\n" );
document.write( "This is the height of the building.<BR>\n" );
document.write( "Hope this helps :-) </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );