document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1021146>Question 1021146</A>: <I><SPAN STYLE=\"word-break: break-all;\"> if xy<0 and y>0 which of the following must be positive?<BR>\n" );
document.write( "A.x-y<BR>\n" );
document.write( "B.2x+3y<BR>\n" );
document.write( "C.x+10/y+2<BR>\n" );
document.write( "D.(-y-2)/x<BR>\n" );
document.write( "E.2y^2+x </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #636902 by </B><A HREF=/tutors/aboutme.mpl?userid=Theo><B>Theo(13342)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Theo><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Theo><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=636902\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> i would say selection D.\r<BR>\n" );
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document.write( "that is:\r<BR>\n" );
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document.write( "(-y-2) / x\r<BR>\n" );
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document.write( "you are given that y > 0.\r<BR>\n" );
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document.write( "you are also given that xy < 0.\r<BR>\n" );
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document.write( "if y > 0, and xy < 0, then x < 0.\r<BR>\n" );
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document.write( "has to be because a negative times a positive is a negative which is less than 0.\r<BR>\n" );
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document.write( "so, if y is positive, x must be negative in order for x times y to be negative.\r<BR>\n" );
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document.write( "of all your options, the only one that has to be positive is eelction D.\r<BR>\n" );
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document.write( "this is because y is positive, therefore -y - 2 has to be negative.\r<BR>\n" );
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document.write( "since x also has to be negative, you get a negative divided by a negative which has to be positive.\r<BR>\n" );
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document.write( "none of the others have to be positive.<BR>\n" );
document.write( "we'll go through each one to show you why.\r<BR>\n" );
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document.write( "A.x-y\r<BR>\n" );
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document.write( "if y is positive and x is negative, then x - y will have to be negative because when you subtract a positive you are adding a negative and a negative (x) plus a negative (-y) is a negative.\r<BR>\n" );
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document.write( "B.2x+3y\r<BR>\n" );
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document.write( "whether thi is positive or negative depends on the values of x and y.<BR>\n" );
document.write( "if x is -20 and y is + 1, then the sum will be negative.\r<BR>\n" );
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document.write( "C.x+10/y+2\r<BR>\n" );
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document.write( "this also depends on the values of x and y.<BR>\n" );
document.write( "if x is more negative than -10, then the numerator will be negative and the denominator will be positive, resulting in a negative.\r<BR>\n" );
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document.write( "D.(-y-2)/x\r<BR>\n" );
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document.write( "y is positive and so -y is negative.<BR>\n" );
document.write( "the numerator has to be negative.<BR>\n" );
document.write( "the denominator has to be negative.<BR>\n" );
document.write( "the result is positive.\r<BR>\n" );
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document.write( "E.2y^2+x \r<BR>\n" );
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document.write( "if x is large enough, then the result will be negative.<BR>\n" );
document.write( "for example, y is 1 and x is - 100.<BR>\n" );
document.write( "y^2 is 1.<BR>\n" );
document.write( "add 1 and -100 and you get a negative number.\r<BR>\n" );
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document.write( "the only one that has to be positive is selection D.\r<BR>\n" );
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document.write( " </SPAN>\n" );
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