document.write( "Question 1021128: What are the dimensions of a rectangle whose length is 4 more than twice the width and whose perimeter is less than 7 times the width?
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Algebra.Com's Answer #636875 by MathTherapy(10552) $\"\"$ $\"About$

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\n" ); document.write( "What are the dimensions of a rectangle whose length is 4 more than twice the width and whose perimeter is less than 7 times the width?
\n" ); document.write( "Please help me out with this question as I've forgotten how to set it up. Thank you.
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Let width be W
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document.write( "Then length or L = 2W + 4
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document.write( "Perimeter = 2(L + W), or 2L + 2W, or 2(2W + 4) + 2W, or 4W + 8 + 2W, or 6W + 8
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document.write( "We then get: 
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document.write( "6W - 7W + 8 < 0 ------- Subtracting 7W from each side
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document.write( "- W + 8 < 0
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document.write( "- W < - 8 ------ Subtracting 8 
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document.write( "Width, or , or \r
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document.write( "L = 2(9) + 4 ------ Substitute 9 for W
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document.write( "L = 18 + 4, or \r
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document.write( "If you substitute a different value for W: the width - one that's greater than 8 - the length's value will change. \n" );
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